thedoctorstatic t1_j27xx6s wrote
Basically to an outside observer, you'll never see it enter the blackhole.
Time at the event horizon from a distant perspective is basically frozen.
The "glow" around the black hole, or the event horizon, is basically our view of everything falling into it, but from the perspective of whatever is falling in, it has already been consumed.
That's not entirely accurate, as it will technically stop being visible to an outside observer eventually, but we're talking an insanely long time period so you wouldn't be able to watch it happen
Cthaeh420 OP t1_j27yh0t wrote
If the string is a defined length, wouldn't the string reach max length from the perspective of the object and start pulling on the anchor point? When this happens, even though the object appears frozen, we would be able to tell its crossed the event horizon? At this point there is no amount of counter force in the universe to bring it back out?
dotslashpunk t1_j2808xq wrote
correct there is no counterforce to bring anything back out of a black hole. More accurately spacetime curves to the degree that “back out” just doesn’t really exist past the event horizon. Think of spacetime curving in in itself (sorta) it’s not even about massive force or not, space is bending in such a way that escape is simply not a path through space.
gameboy1001 t1_j284rju wrote
So, conversely, would the person falling in watch time speed up outside?
Gosh, imagine falling in and watching the universe die with you.
LeMeowMew t1_j286f29 wrote
theoretically assuming the forces dont rip you to shreds, falling into a black hole will be a one way trip to when hawking radiation blows it apart
pestapokalypse t1_j286zc5 wrote
In a supermassive black hole, the tidal forces at the event horizon would actually be relatively weak compared to stellar mass black holes, so it would potentially be feasible to cross the event horizon without being ripped to shreds or spaghettified.
[deleted] t1_j2867mb wrote
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