Viewing a single comment thread. View all comments

sdfree0172 t1_j1gjjti wrote

I think hhhqqqqq1209 gets that. It’s that the 46 billion light years it takes for you to cross the universe is only from the perspective of an observer from earth. However, time is compressed for the traveler as you travel near the speed of light and it is compressed infinitely at the speed of light. So, as the one traveling, you would not experience any time passing and arrive instantaneously (assuming infinite acceleration and deceleration, of course!).

5

flowersonthewall72 t1_j1i28iu wrote

Your relative travel time might have been instantaneous, yes, but the universe around you experienced the relative normal flow of time. So while your trip may have been instantaneous, you've "traveled forward in time" as the universe aged while you were moving at light speed. So sure, your perspective was instant, but your resulting destination was not instant.

1

[deleted] t1_j1grd7f wrote

[deleted]

−3

splittingheirs t1_j1h1mlc wrote

  • T^(trav)= t*(1-v^(2)/c^(2))^(1/2) where:
    t = time observed in the other reference frame
    T^(trav) = time in travelers own frame of reference
    v = the speed of the moving object
    c = the speed of light in a vacuum

observer (t) sees 1 000 000 years go past. Traveler's velocity (v) = c. So:
T^(trav) = 1000000*(1-c^(2)/c^(2))^(1/2)
T^(trav)=1000000*(1-1)^(1/2)
T^(trav)=1000000*(0)^(1/2)
T^(trav)=0
Time experienced by traveler traveling at c = 0 years.

0