rogert2 t1_j6tjfkw wrote
> How big is the supermassive black hole S50014+81 compared to Earth?
To answer that, we divide the black hole's "size" by Earth's "size." And by "size," I think you mean something like diameter. So, the formula is H ÷ E
.
This is a really simple formula, but we have to make sure we're using the same units for it to work.
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The diameter of Earth is 12,756.3 km.
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The black hole's diameter is 1,582 AU, which is a unit of length (like meters), but is still a different unit than kilometers.
So, we either have to convert Earth's size from km to AU, or convert the black hole's size from AU to km. (Let's do the latter.)
1 AU = 149,597,870.7 km
So, the size of the black hole is 1,582 × 149,597,870.7
= 236,663,831,447.4 km.
Now that both are in the same units, we can go back to the original formula and plug in our numbers:
H ÷ E
becomes 236,663,831,447.4 km ÷ 12,756.3 km
= 18,552,701.9 km.
Thus, the black hole is about 18.5 million times as big as Earth.
VesperalRhino t1_j6tl9ku wrote
Thank you for giving a full explanation! And yes you were right I did mean diameter but couldn't think of the word haha. Thank you, I appreciate it!
[deleted] OP t1_j6twrek wrote
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