Submitted by [deleted] t3_124w8vf in explainlikeimfive
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Submitted by [deleted] t3_124w8vf in explainlikeimfive
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A very big issue with this thing, is that bingo isn't exactly a single-player "game". Someone will win, the question is who will win first. Or rather, who gets the luckiest the fastest.
Based on your previous stats, you've won just over 20% of your games (1 in 5). I don't know the mathematical probability of winning at bingo, but based on my experience 20% is very high. You've been lucky.
69/339 = 0.203539 so approximately 0.20 X 100 = 20% chance based on previous results or 1 in 5. https://youtu.be/_YSy85tcFCY
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You'd probably need to provide some more information on the exact rules you play by. For example, if the rules are "Draw balls until someone wins" then each person has a roughly equal chance to win. If you are playing with N total people, that is 1/N. Play alone, and you're certain to win. Play with one other opponent and you will win 1/2 the time. And so on.
But your 20% win rate suggests that you're either playing with small crowds or by some other rules.
It depends on the two following factors :
- how many cards you play with vs the total number of cards
- Does only the first person to finish wins or the first few players?
- What do you count as "a game" (one go starting with fresh cards, or a whole evening with several runs)
I think all these answers are off base. People are trying to calculate the chance of getting 5 in a row, which depends on the numbers,etc…
But every bingo game ends once someone gets Bingo. Assuming everyone has an equal chance of winning, the. Your chance of winning depends only on the number of players.
If you were playing bingo with one person, your probability of winning is 50% (ignoring the possibility of ties)
If you’re playing bingo with 100 people your chance of winning is 1%.
Hi!
We don't actually have any way of knowing.
It feels like you are making one of the many variations of the gamblers fallacy.
Here is what we would need to know to predict odds.
Any special cases for winning aside from simply first to get 5 in a row (that might skew the odd to encourage people to buy/play more cards).
If you held 10 out of 1000 cards in play your likelihood of getting any win condition first would be 10/1000 or 1%.
If you continued to play these odds 100 times, you would likely win once.
Past actions do not change the odds of future games.
Since "the house" usually gets a part of the take, this means your likelihood of losing is bigger than your chance of winning.
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This is not at all how bingo works.
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rwkgaming t1_je153lw wrote
So the reason you are getting a different answer online is because you are likely just doing your odds of winning or rather just your win/los ratio which is far different from the actual probability.
The actual probability is based on the amount of balls in the game and your card. There is a specific calculation for getting the odds for when you then remove odds from the pool which is what you get online.
You could also simplify it and base it on which card you pick at which point it would be 1/x where x is the number of cards since there always has to be one person to win