Submitted by ChrisGnam t3_xwae1i in askscience
Ast0815 t1_ir682my wrote
In short: Yes nucleons can exchange quarks via mesons, but because of confinement the baryons will always have three valence quarks.
But all, e.g., up quarks are indistinguishable. So it makes no sense to say that a particular quarks left the proton and travelled to another (as part of a pion for example). At the same time a new up-quark must have been created and remained in the original proton.
And then there is the issue of energy scale. The quarks are still bound inside the nucleons, meaning the energy required to get one out is larger than the random energy fluctuations in the system (= temperature). That is why you only exchange virtual mesons rather than real particles. Mathematically this makes it convenient to describe the nucleons as their own things that than interact with one another, rather than looking at all the quarks and gluons and whatnot separately.
You can create states of matter where the quarks are no longer bound, i.e. it makes sense to model things on the quark level. It is called "quark gluon plasma", and it exists at much higher energies/temperatures. E.g. it is created briefly in particle colliders, when you smash nuclei into each other.
K_H007 t1_ir72ldv wrote
QG Plasma also potentially happens in the cores of Neutron Stars. IIRC, the term for such Neutron Stars is a "Quark Star".
JahnBitWaf t1_ir95s1z wrote
And it happens when a new universe is born but only up to about a millionth of a second.
TheProfessorOfNames t1_ir983iy wrote
What exactly is a "virtual" meson?
RobusEtCeleritas t1_ir9bufp wrote
There's good info about this in our FAQ.
TheProfessorOfNames t1_irb1v2k wrote
Thank you!
[deleted] t1_ir9bhug wrote
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Zelrak t1_ir9ws1e wrote
Q from someone with high energy theory background but who didn't do much nuclear physics: Given that the nucleus is in a strong coupling regime, what does it mean to talk about a perturbative picture of nuclei exchanging mesons? I always thought of the nucleus as a bag of stuff we don't understand and all we can say is that the whole bag has some given colour, baryon, etc charges, where you can measure form factors and such other phenomenological parameters
[deleted] t1_ir9yrsf wrote
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