Yup! If you look at the graph of tanh you will see relu(tanh) will smush the left half of the graph to 0. The right half of the graph on (0,infty) ranges in value from 0 and 1 but you can see saturation towards 1 starts to occur around 2-2.5. Since relu leaves this half unchanged you’ll be able to approach 1 very effectively with reasonable finite values.